32 lines
1.1 KiB
Python
32 lines
1.1 KiB
Python
import structio
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async def child(i: int, sem: structio.Semaphore):
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print(f"[child {i}] I'm alive!")
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async with sem:
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print(f"[child {i}] Entered critical section")
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await structio.sleep(1)
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print(f"[child {i}] Exited critical section")
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async def main(n: int, k):
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assert isinstance(n, int) and n > 0
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assert isinstance(k, int) and k > 1
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print(f"[main] Parent is alive, creating semaphore of size {n}")
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semaphore = structio.Semaphore(n)
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t = structio.clock()
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async with structio.create_pool() as pool:
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print(f"[main] Spawning {n * k} children")
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for i in range(1, (n * k) + 1):
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pool.spawn(child, i, semaphore)
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print("[main] All children spawned, waiting for completion")
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# Since our semaphore has a limit of n tasks that
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# can acquire it concurrently, we should see at most
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# n instances of child running at any given time,
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# like in batches
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print(f"[main] Done in {structio.clock() - t:.2f} seconds")
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# Should exit in about k seconds
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structio.run(main, 3, 2)
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